**Mindtree Aptitude Questions and Answers For Freshers:** Well, those who are preparing for Mindtree test can check this page of Mindtree Aptitude Questions and Answers. These are given for the sake of Freshers (2018, 2019 & 2020 Batches). If you are willing to attempt the Mindtree exam, then test your skills by solving sample Mindtree Aptitude Questions and Answers with Explanation.

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Contents

## Mindtree Aptitude Questions and Answers For Freshers (2018, 2019 & 2020 Passed outs)

**Number of Questions:** 25 Questions

**Time Duration:** 35 Mins

**You Can Also Check: Mindtree Syllabus**

Topics | Questions asked (Approximately) |
---|---|

Averages | 2-4 Questions |

Profit and Loss | 3-5 Questions |

Time and Work | 2-4 Questions |

Percentages | 2-5 Questions |

Time and Distance | 3-4 Questions |

Quadratic Equations | 3-5 Questions |

Races and Games | 1-4 Questions |

Mixtures and Allegations | 2-3 Questions |

Simple Interest | 3-5 Questions |

Compound Interest | 2-3 Questions |

Simplification | 3-6 Questions |

Areas | 2-5 Questions |

Simple Equations | 3-5 Questions |

Mensuration | 2-4 Questions |

Boats and Streams | 1-3Questions |

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### Mindtree Aptitude Questions and Answers with Solutions

The officials of Mindtree are providing excellent career opportunities, especially for freshers. Therefore, candidates who had applied for Mindtree drive. Those applicants have a look at Mindtree Aptitude Questions and Answers with Explanation and build your confidence level. The main key for each and every student is time management in the written test. You can manage your time by solving more and more sample Mindtree Aptitude Questions and Answers. Moreover, these may be the question which is going to repeat in the exam, so be careful and go through each and every question that are arranged in the below section. You can download Mindtree Aptitude Questions and Answers in PDF format at the end of this article.

### Mindtree Aptitude Questions and Answers with Explanation

1. **8 4.5 5.5 13 56 ?**

A. 456

B. 436

C. 526

D. 556

**Answer –** A. 456

**Explanation:**

8*0.5 + 0.5 = 4.5

4.5*1 + 1 = 5.5

5.5*2 + 2 = 13

13*4 + 4 = 56

Therefore, 56*8 + 8 = 456

2. **15 , 22, 72, 552 , ?**

A. 4500

B. 4592

C. 4763

D. 8800

**Answer –** D. 8800

**Explanation:**

15×2 – 8 = 22

22×4 – 16 = 72

72×8 – 24 = 552

552×16 – 32 = 8800

3. **1650, ?, 50, 9.5, 1.17, -0.415**

A. 270

B. 560

C. 750

D. 1050

**Answer –** A. 270

**Explanation:**

1650/6 – 5 = 275 – 5 = 270

270/5 -4 = 54-4 = 50

50/4 -3 = 12.5 -3 = 9.5

9.5/3 -2 = 3.17-2 = 1.17

1.17/2 -1 = 0.585-1 = -0.415

4.** ?, 104, 41.6. 24.96, 19.97**

A. 350

B. 370

C. 520

D. 630

**Answer –** C. 520

**Explanation:**

520*1/5 =104

104*2/5= 41.6

41.6*3/5 = 24.96

24.96*4/5 = 19.97

5. **5 12 33 136 675 ?**

A. 3850

B. 3950

C. 3460

D. 4056

**Answer –** D. 4056

**Explanation:**

5 * 2 + 2 = 12

12 * 3 – 3 = 33

33 * 4 + 4 = 136

136 * 5 – 5 = 675

Therefore, 675 * 6 + 6 = 4056.

6. **By selling 15 oranges, a fruit seller gains the selling price of 1 orange. Calculate his gain percentage**

A. 6.14%

B. 7.14%

C. 8%

D. 8.41%

**Answer –** B. 7.14%

**Explanation:**

Selling Price of 1orange = 1

Then, Selling Price of 15 orange will be = 15

Profit = 1

CP = 15 – 1 = 14

Profit % = (1/14)×100 = 7.14%

7. **Ravi bought 30 liters of milk at the rate of Rs.8 per liter. He got it churned after spending Rs.10 and 5kg of cream and 30 liters of toned milk was obtained. If he sold the cream at Rs.30 per kg and toned milk at Rs.4 per liter, his profit in the transaction is:**

A. 8%

B. 20%

C. 30%

D. 40%

**Answer –** A. 8%

**Explanation:**

CP =Rs.(30 x 8 + 10) = Rs.250

SP = Rs. (30 x 5 + 30 x 4) = Rs.270

Gain% = (20/250 x 100)% = 8%

8. **The sale price of an article including the sale tax is Rs. 616. The rate of sale tax is 10 %. If the shopkeeper has made a profit of 12%, the cost price of the article is**

A. Rs 500

B. Rs 515

C. Rs 550

D. Rs 600

**Answer –** A. Rs 500

**Explanation:**

110% of S.P = 616

Then, S.P. = Rs.(616 x 100/110) = Rs.560.

C.P. = Rs (100/112 x 560)

= Rs 500

9.** Prasanth drove at the speed of 45 kmph. From home to a resort. Returning over the same route, he got stuck in traffic and took an hour longer, also he could drive only at the speed of 40 kmph. How many kilometers did he drive each way?**

A. 360km

B. 420km

C. 480km

D. 720km

**Answer –** A. 360km

**Explanation:**

According to the given data

x/40 – x/45 = 1

9x-8x/360 = 1

x/360 = 1

x = 360km

10.** Walking at the rate of 4 kmph a man covered a certain distance in 2 hrs 30min. Running at a speed of 17.5 kmph the man cover the same distance in how many mins?**

A. 19 min

B. 26 min

C. 34 min

D. 42 min

**Answer –** C. 34 min

**Explanation:**

4*(2+30/60) = 4*2.5 = 10 km

17.5 kmph then T= 10/17.5 =100/175

= 20/35 = 4/7

Time = 4*60/7 = 34 min

11. **Hemanth has to travel from one point to another point at a certain time. Traveling at a speed of 6 kmph he reaches 40 m late and traveling at a speed of 8 kmph he reaches 12 m earlier. What is the distance between these two points?**

A. 15 km

B. 18 km

C. 21 km

D. 27 km

**Answer –** C. 21 km

**Explanation:**

D/6 – 40/60 = d/8 +12/60

d/6 – d/8 = 12/60+40/60

(8-6)d/48 = 52/60

2d/48 = 52/60

D = 52*48/60*2 = 20.8 = 21 km

12.** The present age of Husband and Wife is 28 and 24 Years respectively. At that age, twin babies were born to them. After how many years the average of the family will be the same as before babies were born?**

A. 10 Years

B. 11 Years

C. 12 Years

D. 13 Years

**Answer –** D. 13 Years

**Explanation:**

According to the given data

28+24/2 =26 = (28+x+24+x+2x)/4

104 = (52+4x)

x= 13

13. **A can do a work in 32 days. B who is 60 percent more efficient than A. Find how much time they will take together to do the same work?**

A. 150/13 days

B. 160/13 days

C. 170/3 days

D. 190/3 days

**Answer –** B. 160/13 days

**Explanation:**

A’s one-day work = 1/32

Therefore, B one day work = (160/100)*1/32 = 1/20

Then, B will take 20 days to complete the work.

So Both A and B will take = (32*20)/52 = 160/13 days

Hence it is proved.

14.** 50 men could complete work in 200 days. They worked together for 150 days, after that due to bad weather the work is stopped for 25 days. How many more workers should be employed so as to complete the work in time?**

A. 25

B. 35

C. 50

D. 60

**Answer –** C. 50

**Explanation:**

Let additional workers be P

Then, (50*150)/(50*200) = 3/4 of the work is already completed and now only 1/4 of the work is to be done.

Therefore, 1/4 = ((50 + P) * 25)/50*200, solve for p, we get P = 50

Hence, more workers should be employed so as to complete the work in time = 50

15.** Abhishek takes thrice as long to row a distance against the stream as to row the same distance in favor of the stream. The ratio of the speed of the boat in still water and stream is**

A. 1: 2

B. 2: 1

C. 2: 3

D. 3: 1

**Answer –** B. 2: 1

**Explanation:**

speed downstream = x kmph

Speed upstream = 3x kmph

(3x+x)/2 : (3x-x)/2

4x/2 : 2x/2 = 2: 1

16. **A boat can travel 4.2 km upstream in 14 min. If the ratio of the speed of the boat in still water to the speed of the stream is 7:1. How much time will the boat take to cover 17.6 km downstream?**

A. 32 min

B. 48 min

C. 56 min

D. 44 min

**Answer –** D. 44 min

**Explanation:**

Speed = 7x: x

Downstream = 8x; upstream = 6x

Upstream speed = 4.2*60/14 = 18 kmph

6x = 18

X = 3

Downstream = 8*3 = 24

Time taken for 17.6 km = 17.6*60/24 = 44 min

17. **A man can row at 4 kmph in still water. If the velocity of the current is 1 kmph and it takes him 1 hour to row to a place and come back. how far is that place?**

A. 1.5 km

B. 1.8 km

C. 2.6 km

D. 3.2 km

**Answer –** B. 1.8 km

**Explanation:**

Let the distance is x km

Rate downstream = 4 + 1 = 5 kmph

Rate upstream = 4 – 1 = 3 kmph

then

x/5 + x/3 = 1

3x + 5x = 15

x = 15/8 = 1.8 km

18. **A boat takes 30 hours for traveling downstream from point A to point B and coming back to point C midway between A and B. If the velocity of the stream is 2 kmph and the speed of the boat in still water is 15 kmph, what is the distance between A and B?**

A. 308 km

B. 316 km

C. 342 km

D. 356 km

**Answer –** A. 308km

**Explanation:**

The velocity of the stream = 2 kmph

The speed of the boat in still water is 15 kmph

Speed downstream = (15+2) = 17 kmph

Speed upstream = (15-2) = 13 kmph

Let the distance between A and B be x km

x/17+(x/2)/13=30

x/17+x/26=30

43x/442=30

x=30*442/43 = 308.37 = 308 km

the distance between A and B = 308 km

19. **Varun got 5000 as his share out of the total profit of 9000. Dhaval had invested 3000 rupees for 6 months while Varun invested for the whole year. Find the amount invested by Varun.**

A. 1875

B. 1975

C. 2125

D. 2275

**Answer –** A. 1875

**Explanation:**

Amount invested by Varun = P

12 P: 3000*6

P:1500

So Varun share = [p/(1500+p)]*9000 = 5000

P = 75*25 = 1875

Therefore, Amount invested by Varun is 1875

20. **A and B invested in a business in which A invest 250 rupee more than B. B invested for 6 months while A invested for 4 months. If A gets 200 more than B out of a total profit of 1000. Then the total amount invested in the business.**

A. 550

B. 650

C. 750

D. 850

**Answer –** B. 650

**Explanation:**

Let B invest ‘x’ rupees so A will invest (x+250)

Total investment made by A = (x+250)*4 and by B = 6x

According to the problem- [[4(x+250) – 6x]/(1000+ 10x)]*1000 = 200.

X = 200. Total investment = 200+250+200 = 650

21. **The average temperature in Delhi for the first four days of the month was reported as 58 degrees. It reported as 60 degrees for 2nd, 3rd, 4th and 5th days. The ratio of the temperatures of 1st and 5th day was 7: 8. Find the temperature on the first day.**

A. 42 degrees

B. 46 degrees

C. 56 degrees

D. 68 degrees

**Answer –** C. 56 degrees

**Explanation:**

A+B+C+D = 58*4

B+C+D+E = 60*4

Subtract both, E-A = 8

So 8x – 7x = 8, x = 8

So temperature of A(1st day) = 7x = 7*8 = 56 degrees

22. **In a group of 8 boys, 2 men aged at 21 and 23 were replaced, two new boys. Due to this the average cost of the group increased by 2 years. What is the average age of the 2 new boys?**

A. 17

B. 28

C. 23

D. 30

**Answer –** D. 30

**Explanation:**

Average of 8 boys increased by 2, this means the total age of boys increased by 8*2 = 16 yrs

So sum of ages of two new boys = 21+23+16 = 60

Average of these = 60/2 = 30

23. **One year ago the ratio between Rahul salary and Rohit salary is 4:5. The ratio between their individual salary of the last year and the current year is 2:3 and 3:5 respectively. If the total current salary of Rahul and Rohit is 4300. Then find the current salary of Rahul.**

A. 1200

B. 1800

C. 1600

D. 2000

**Answer –** B. 1800

**Explanation:**

4x and 5x is the last year salary of Rahul and Rohit respectively

Rahul last year to Rahul current year = 2/3

Rohit last year to Rohit current year = 3/5

Current of Rahul + current of Rohit = 4300

(3/2)*4x + (5/3)*5x = 4300.

X = 300.

So Rahul current salary = 3/2 * 4* 300 = 1800

24. **A bag contains 25p coins, 50p coins and 1 rupee coins whose values are in the ratio of 8:4:2. The total values of coins are 840. Then find the total number of coins**

A. 260

B. 280

C. 220

D. 240

**Answer –** B. 280

**Explanation:**

Value is given in the ratio 8:4:2.

(8x/0.25) + (4x/0.5) + (2x/1) = 840.

X = 20. Total amount = 14*20 = 280

25. **Two vessels contain an equal quantity of solution contains milk and water in the ratio of 7:2 and 4:5 respectively. Now the solutions are mixed with each other then find the ratio of milk and water in the final solution?**

A. 11:5

B. 11:6

C. 11:7

D. 11:9

**Answer –** C. 11:7

**Explanation:**

milk = 7/9 and water = 2/9 – in 1st vessel

milk = 4/9 and water = 5/9 – in 2nd vessel

(7/9 + 4/9)/ (2/9 + 5/9) = 11:7

### Mindtree Aptitude Questions and Answers in PDF format

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