**Problems On Trains Aptitude Questions and Answers | MCQ Problems: **Everyone knows that solving the Problems On Trains in aptitude is a very difficult task. Moreover, you have to know about the **Problems With Trains Tricks, Formulas**. So, to give a clear idea, we have given some simple and easy tricks about solving Problems on Trains Questions and Answers easily. At the bottom of this article, we have arranged the **Problems on Trains MCQ Online Test**. So, simply take the Online Test and gain a complete grip on Train Problems in Aptitude.

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## Problems On Trains Overview – Aptitude Test

Quiz Name |
Problems On Trains |

Category |
Aptitude |

Number of Questions |
25 |

Time |
30 Minutes |

Exam Type |
MCQ (Multiple Choice Questions) |

## Problems on Trains MCQ Quiz – Practice Here

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**1. Train A is in station P in platform no. 4 and train B is in station Q. Distance between the two stations is 3 km. Both the trains are on the same track. Train A starts towards Q and train B towards P. There is a point to change track at a 600-meter distance from station P. Train A changes the track so that train B comes and stops at platform number 4 of station P. Find the distance between the track point to train B when train A crosses the track point. Speed of train A is 72 km/hour and the speed of train B is 36 km/hour?**

a) 1422 m

b) 1472 m

c) 2100 m

d) 1596 m

e) 1245 m

**Answer: C**

**Explanation:**

To goes 600 m train A takes 600/(72*5/18)=30 sec

So, in 30-sec train B travels 30*36*5/18=300 m

Track point is situated 3000-600=2400 m from station Q.

So, we train A cross-track train B is 2400- 300=2100 m distance from track point.

**2. Train A crosses a tree in 17.5 seconds and also crosses a 250m long platform in 30 seconds. If the length of train B is 50 m less than that of A and the speed of train B is 18 kmph more than that of A, then find the time taken by train B crosses a 150m long tunnel.**

a) 24 seconds

b) 12 seconds

c) 18 seconds

d) 36 seconds

e) None of these

**Answer: C**

**Explanation:**

Length of train A = x

Speed of train A = y

x = y * 5/18 * 17.5

x = 87.5y/18

x + 250 = y * 5/18 * 30

87.5y/18 + 250 = 25y/3

62.5y/6=750

y = 72

x = 350

Length of train B = 350 – 50 = 300 m

Speed of train B = 72 + 18 = 90 kmph

Required time = (300 + 150)/90 * 5/18 = 18 seconds

**3. The length of train A is 25% more than that of train B and the speed of train A is 20% more than that of B. If train A crosses a tree in 12 seconds and also crosses train B running in the same direction in 162 seconds, then find the speed of train B.**

a) 100 kmph

b) 60 kmph

c) 90 kmph

d) 50 kmph

e) Cannot be determined

**Answer: B**

**Explanation:**

Let the length of train B be L and its speed be S.

Then, the length of train A is 1.25L (25% more than that of train B), and its speed is 1.2S (20% more than that of train B).

When train A crosses a tree in 12 seconds, we can use the formula:

distance = speed × time

Let the distance between the tree and the starting point of train A be D. Then, we have:

1.2S × 12 = D

D = 14.4S

When train A crosses train B running in the same direction, we can use the formula:

relative speed = speed of A – speed of B

Let the distance between the two trains be X. Then, we have:

1.2S – S = 0.2S (the relative speed)

X = (1.25L + L) = 2.25L (the relative distance)

So, we have:

time = distance / relative speed

162 = 2.25L / 0.2S

Solving for L, we get:

L = 450 / S

Substituting this value of L in the equation for the relative distance, we get:

X = 2.25 × (450 / S) = 1012.5 / S

Now, we can use the formula for the time taken by train A to cross train B:

time = distance / relative speed

time = X / (1.2S – S) = X / 0.2S

Substituting the values of X and S, we get:

162 = (1012.5 / S) / (0.2S)

Solving for S, we get:

S = 60 kmph

Therefore, the speed of train B is 60 kmph, which is option (b).

**4. Train A crosses 200 m long tunnel in 30 seconds and train B also crosses the same tunnel in 18 seconds and the speed of train B is 50% more than the speed of train A. If the difference between the speed of train A and B is 30 kmph, then find the time taken by train A crosses train B running in same direction?**

a) 54 seconds

b) 48 seconds

c) 66 seconds

d) 72 seconds

e) 90 seconds

**Answer: C**

**Explanation:**

Speed of train A = 2x

Speed of train B = 2x * 150/100 = 3x

3x – 2x = 30x = 30

Speed of train A = 2 * 30 = 60 kmph

Speed of train B = 3 * 30 = 90 kmph

Length of train A=x

Length of train B=y

200 + x=60 * 5/18 * 30

x =300 m y + 200=90 * 5/18 * 18

y =250

Required time = (300 + 250)/30 * 5/18 = 66 seconds

**5. The ratio between the speed of a train and a bus is 8:5 respectively. Also, a car covered a distance of 320km in 10hrs. The speed of car is half the speed of the train. Find the speed of bus**

a) 40 km/hr

b) 45 km/hr

c) 48 km/hr

d) 58 km/hr

e) 50 km/hr

**Answer: A**

**Explanation: **

**6. A 240m train A crosses another 300m long train B running in the same direction in 36sec. If the speed of train A be 54km/hr which is lesser than the speed of train B, then what is the speed of second train?**

a) 20m/sec

b) 30m/sec

c) 25m/sec

d) 35m/sec

e) 40m/sec

**Answer: B**

**Explanation: **

**7. Two trains (train A and Train B) of length 150m and 200m respectively with the same speed pass a tree in 6sec and 20sec respectively. In what time they will cross each other if they are moving in opposite directions?**

a) 12 sec

b) 11 sec

c) 20 sec

d) 9 sec

e) 10 sec

**Answer: E**

**Explanation: **

**8. A train crosses a bridge of 400 m in 65 seconds. Speed of train is 36 km/hour. How long it will take to cross a platform of length 350 m?**

a) 2 minutes

b) 1 minute

c) 40 second

d) 45 second

e) 50 second

**Answer: B**

**Explanation:**

Speed of train = 36 x 5/18 = 10 m/s

In 65 seconds, it will cover = 650 m

Length of train = 650 – 400 = 250 m

Time taken by train to cover platform of 350 m

Distance = 250 + 350 = 600 m

Speed = 10 m/s

∴ Time = 600/ 10 = 60 seconds = 1 minute

**9. Train A crosses a platform of length 400 m in 40 sec. Speed of Train A is 20 m/s and length of Train B is two-fifth the length of Train A . Find the length of train B .**

a) 160 m

b) 200 m

c) 180 m

d) 220 m

e) 120 m

**Answer: A**

**Explanation:**

Train A travel distance in 40 sec = 40 × 20 = 800 m

Length of train A = 800 – 400 = 400 m

Length of Train B = 400 × 2/5 = 160 m

**10. A passenger train departs from Chennai at 8pm. for Madurai. At 11 p.m an express train, whose average speed exceeds that of the passenger train by 15 km/hr, leaves Madurai for Chennai. Two trains meet each other mid-route. At what time do they meet, given that the distance between the cities is 1080 km?**

a) 8 a.m

b) 8:30 p.m

c) 12 mid-nigh

d) 4 a.m

e) None of these

**Answer: A**

**Explanation:**

Let speed of passenger train = x

Speed of express train = x +15

Let they meet after t hour

So distance travelled by both is same = 1080/2 = 540

Distance travelled by passenger train = x(t+3)

Distance travelled by express train = (x + 15)t

=> x(t+3) = (x + 15)t

x = 5t

Total distance = 1080

x(t+3) + (x + 15)t = 1080

t2+ 3t-108 = 0

(t-9)*(t+12)=0

so t = 9, – 12 (-12 hrs not acceptable time can’t be negative)

They meet after 9 hours

Time = 11:00 pm+ 9 hours = 8:00 am

**11. Q. The distance between two stations A and B is 800 km. A train x starts from A and moves towards B at 40km/h and another train Y starts from B and moves towards A at 60km/h. How far from A will they cross each other?**

a) 380 km

b) 320 km

c) 300 km

d) 360 km

e) None

**Answer: B**

**Explanation:**

**12. A train leaves a station A at 7 am and reaches another station B at 11 am. Another train leaves B to 8 am and reaches A at 11:30 am. The two trains cross one another at**

a) 8:36 AM

b) 8:56 AM

c) 9:00 AM

d) 9:24 AM

e) None

**Answer: D**

**Explanation:**

Kindly refer to the video or go through the explanation given below :

Let the distance between the stations A & B be 4 kms.

∴ Speed A → B = 4/4=1 km/hr

& Speed B → A = 4/(7/2)=8/7km/hr

Suppose they meet x hours after 8 am.

Distance covered by both the trains to meet each other = Distance covered by them from 8 am

(1+8/7)*x=3kms

=15/7 x=3

∴ They will meet at 9 : 24 AM. (After adding 1 hr 24 mins to 8 am.)

Hence, option D is correct.

**13. If a train runs with the speed of 84 km/hr, it reaches its destination late by 25 minutes. However, if its speed is 98 km/hr, it is late by 10 minutes only. The right time for the train to cover its journey is –**

a) 60 minutes

b) 80 minutes

c) 75 minutes

d) 92 minutes

e) None

**Answer: B**

**Explanation:**

Let t be the right time

84(t + 25) = 98(t + 10)

6(t + 25) = 7(t + 10)

150 – 70 = t

t = 80 min

**14. A 720m long train takes 96 seconds more to cross a platform than it takes to cross a pole at the same speed. Given that the length of platform is twice the length of train. What is the speed of train in km/h ?**

a) 36

b) 54

c) 45.5

d) 64.4

e) None

**Answer: B**

**Explanation:**

**15. A train starts at 11:00 am from point A towards point B at 36 km /h while a car starts at 1:00 pm from point B towards point A at 44 km/h. They cover a distance of 712 km till the meeting. At what time will they meet each other?**

a) 7:30 pm

b) 8:00 pm

c) 8:30 pm

d) 9:00 pm

e) None

**Answer: D**

**Explanation: **

**16. The distance between Navi Mumbai and Kolhapur is 330km on a straight line. ‘Koyna Express’ starts from Mumbai at exactly 9 pm towards Kolhapur with a speed of 60km/hr. While, ‘Mahalaxmi express’ starts from Kolhapur at exactly 10 pm towards Mumbai with a speed of 75 km/hr. At what time do these two trains will meet during their travel?**

a) 1:00am

b) 10.20 pm

c) 12.30 am

d) 12 midnight

e) None

**Answer: D**

**Explanation:**

⇒Suppose Koyna Express and Mahalaxmi express meet each other ‘a’ hours after 9 pm.

⇒Distance covered by Koyna Express in ‘a’ hours = 60a km

⇒Distance covered by Mahalaxmi Express in (a – 1) hrs = 75 (a – 1) km

⇒60a + 75 (a – 1) = 330

⇒60a + 75a -75 =330

⇒135a = 405

⇒a = 3

⇒Two trains will meet after 3 hours of 9 pm .ie. 12 midnight

**17. A man in a train notices that he can count 96 electric posts in one minute. If they are known to be 60 m apart, then what is the speed of the train?**

a) 96km/h

b) 342m/s

c) 95km/h

d) 342km/h

e) None

**Answer: B**

**Explanation: **

**18. Two trains running in opposite directions on parallel tracks, at speeds of 33 km/hr and 39 km/hr, take 23 seconds to cross each other. If the length of one train is 250 m, then the length of the other train is:**

a) 210 m

b) 225 m

c) 240 m

d) 190 m

e) None

**Answer: A**

**Explanation: **

**19. Two trains running in opposite directions on parallel tracks, at speeds of 37 km/hr and 44 km/hr, take 24 seconds to cross each other. If the length of one train is 265 m, then the length of the other train is:**

a) 210 m

b) 225 m

c) 275 m

d) 250 m

e) None

**Answer: C**

**Explanation: **

**20. Aman’s speed with the current is 15 km/hr and the speed of the current is 2.5 km/hr. The man’s speed against the current is :**

a) 9.5 km/hr

b) 10 km/hr

c) 10.5 km/hr

d) 11 km/hr

e) None

**Answer: B**

**Explanation:**

Man’s rate in still water = (15 – 2.5) km/hr = 12.5 km/hr.

Therefore, Man’s rate against the current = (12.5 – 2.5) = 10 km/hr.

**21. A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is ?**

a) 45 kmph

b) 25 kmph

c) 30 kmph

d) 50 kmph

e) None

**Answer: D**

**Explanation:**

Speed of the train relative to man = (125/10) m/sec = (25/2) m/sec.

[(25/2) x (18/5)] km/hr = 45 km/hr.

Let the speed of the train be ‘S’ km/hr.

Then, relative speed = (S – 5) km/hr.

S – 5 = 45 => S = 50 km/hr.

**22. A train 150 m long passes a pole in 15 seconds and crosses another train of the same length travelling in opposite direction in 8 seconds. The speed of the second train in (km/h) is**

a) 60 km/hr

b) 66 km/hr

c) 72 km/hr

d) 99 km/hr

e) None

**Answer: D**

**Explanation:**

Speed of the first train = 150/50=10 m/sec

Let the speed of the second train be x m/sec

Relative speed = (10 + x)m/sec

Length of train 1 + length of train 2 = 150 + 150 = 300 mtr

In the second scenario equation will be like 300/10+x=8

or, 300 = 80 + 8x

or, x = 220/8=55/2m/sec

∴ speed of the second train = 55/2*18/5=99km/hr

Hence, option D is correct.

**23. A goods train runs at the speed of 72 kmph and crosses a 250 m long platform in 26 seconds. What is the length of the goods train?**

a) 230 m

b) 240 m

c) 260 m

d) 270 m

e) None

**Answer: D**

**Explanation:**

Speed =[ 72 x (5/18) ]m/sec= 20 m/sec.

Time = 26 sec.

Let the length of the train be x metres.

Then,[ (x+250)/26 ]= 20

=> x + 250 = 520

=> x = 270.

**24. Two stations P and Q are 110 km apart on a straight track. One train starts from P at 7 a.m. and travels towards Q at 20 kmph. Another train starts from Q at 8 a.m. and travels towards P at a speed of 25 kmph. At what time will they meet?**

a) 10.30

b) 10

c) 8.45

d) 9.30

e) None

**Answer: B**

**Explanation:**

Assume both trains meet after x hours after 7 am

Distance covered by train starting from P in x hours = 20x km

Distance covered by train starting from Q in (x-1) hours = 25(x-1)

Total distance = 110

=> 20x + 25(x-1) = 110

=> 45x = 135

=> x= 3

Means, they meet after 3 hours after 7 am, ie, they meet at 10 am

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## Problems on Trains Aptitude Questions and Answers

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