Take **Simple Equations Quiz Online Test** to calculate your knowledge over the scale. Now, Simple Equations is as same as the** Linear Equations**. Now, most of the universities or the organization or the companies are including the **Simple Equations Topics i**n the Aptitude Test. And this is troubling many of the aspirants. Because most of them had no idea of solving the **Simple Equations Aptitude**. Therefore, to help all such contenders, we are providing some reliable sources through this post. Well, along with on this particular page we are also providing some Simple Equations Tricks and Concepts too. So, all the people who are thinking on getting the knowledge can proceed and check them. Well, along with that, you can even take the **Simple Equations** Quiz also. This is absolutely free. Now, we have framed approximately 15 Questions. And that is going to cover all the important topics.

## Simple Equations Quiz

Quiz Name |
Simple Equations |

Category |
Aptitude |

Number of Questions |
15 |

Time |
30 Minutes |

Exam Type |
MCQ (Multiple Choice Questions) |

## Simple Equations Online Test – Practice Now

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**1. What is an equation?**

A. A statement in which the values of two mathematical expressions are equal.

B. An expression that computes the values of variables.

C. A mathematical expression.

D. None of these

**Answer: A**

**Explanation: **An equation is a mathematical statement which represents two things are equal. It consists of two expressions, one on either side of equal to symbol. In other words, an equation is a statement in which the values of two mathematical expressions are equal.

**2. Sumeet guessed a number x and then he added 30 to it. Give the expression for double of it.**

A. 2(x+30)

B. 2(x+30)1

C. 2x+30

D. x+60

**Answer: A**

**Explanation: **

According to the question,

The expression is x+30.

∴ double of it will be 2(x+30).

**3. Frame the given statement into a mathematical expression: “Thrice of a number increased by 150.”**

A. 150−x

B. 3x−150

C. 3x+150

D. None of these

**Answer: C**

**Explanation: **

Let x be the required number.

∴ thrice of a number shall be 3×x=3x.

According to the question, if it is increased by 150,

the number would be (3x+150).

**4. Frame the statement “Twice a number decreased by 119 equals 373” into an equation.**

A. 2y+119=373

B. 3y−119=373

C. 2y−119=373

D. None of the above.

**Answer: C**

**Explanation: **

Let y be the number.

According to the question,

Twice a number y, decreased by 119 means

2y−119=373.

So, option C is correct.

**5. Which of the sign should always be there in an equation?**

A. =

B. =

C. >

D. <

**Answer: A**

**Explanation: **

An equation is a mathematical statement that two things are equal. It consists of two expressions, one on each side of an ‘equals’ sign. For example x=y is an equation where two expressions x and y are equal.

Hence, = sign should always be there in an equation.

**6. Algebraic expression for the statement: 6 times a taken away from 40**

A. 6a−40

B. 40a−6

C. 40−6a

D. 0

**Answer: C**

**Explanation: **

Given, 6 times a takes away from 40.

Required algebraic equation is given by,

40−6×a=40−6a

∴x=8

**7. Convert the statement into an equation : Adding 14 to 9 times y is 89.**

A. 14y+9=89

B. 14+9y=89

C. 14−9y=−89

D. 14+y=89

**Answer: B**

**Explanation: **

According to the question,

9 times y means 9×y=9y.

Adding 14 to it means 9y+14.

∴ the equation is 9y+14=89.

**8. Sunita’s mother is 36 years old. She is 3 years older than 3 times sunita’s age. What is sunita’s age?**

A. 6

B. 7

C. 8

D. 11

E. 14

**Answer: D**

**Explanation: **

We do not know sunita’s age.

Let us take it to be y years. .

Sunita’s mother’s age is 3years older than 3y;

It is also given that Sunita’s mother is 36 years old.

Therefore, 3y+3=36

Subract 3 from both side

3y+3−3=36−3

3y=33

Divide both side by 3

y=11

**9. The arithmetic mean of 6,10, x and 12 is 8 The value of x is**

A. 3

B. 4

C. 5

D. 6

**Answer: B**

**Explanation: **

Arithmetic Mean =Total number of terms / Sum of the terms

⇒8=46+10+x+12

⇒32=6+10+x+12

⇒x=32−28

⇒x=4

**10. Frame the statement into an equation: Adding 16 to 3 times x is 39.**

A. 3x−16=39

B. 3x+16=−39

C. −3x+16=39

D. 3x+16=39

**Answer: D**

**Explanation: **

3×x=3x

As per the given condition,

Adding 16 to 3x results in 16+3x=39

So, option D is correct.

**11. The method of finding solution by trying out various values for the variable is called**

A. Rrror method

B. Trial and error method

C. Testing method

D. Checking method

**Answer: B**

**Explanation: **

The required method is called “Trial and error method”

**12. Find the value of x: x−7=−8**

A. 1

B. −1

C. 0

D. None of the above

**Answer: B**

**Explanation: **

x−7=−8

Add 7 to both sides,

⟹x−7+7=−8+7

⟹x=−8+7

⟹x=−1

Hence, answer is option B.

**13. The mean of x,x+3,x+6,x+9 and x+12 is**

A. x+6

B. x+3

C. x+9

D. x+12

**Answer: A**

**Explanation: **

By definition,

Average=5x+(x+3)+(x+6)+(x+9)+(x+12) ÷ 5

=5x+30÷ 5 =x+6

**14. Solve the following equation: 6=z+2**

A. 4

B. 2

C. 6

D. 8

**Answer: A**

**Explanation: **

Given, 6=z+2

Subtract 2 on both the sides,

6−2=z+2−2

⇒z=4

Hence, option A is correct.

**15. When 6 is subtracted from four times a number, the result is 54. What is the number?**

A. 60

B. 30

C. 15

D. 10

**Answer: C**

**Explanation: **

Let the number be x.

Then, 4x−6=54

Add 6 on both side

⇒4x−6+6=54+6=>4x=60

Divide throughout by 4

⇒x=60 /4 /=15

Hence, the required number is 15.

**16. The solution of the equation 7+3(x+5)=31 is**

A. 4

B. 3

C. 0

D. 2

**Answer: B**

**Explanation: **

Given, 7+3(x+5)=31

⇒7+3x+15=31

⇒22+3x=31

⇒3x=31−22=9

⇒x=9/3=3.

Hence, the required solution is x=3.

**17. If 6x=12, then x is**

A. 12

B. 2

C. 72

D. 6

**Answer: B**

**Explanation: **

Given, 6x=12

Dividing both sides by 6, we get:

6x/6 =12x/6

∴ x=2

Hence, option B is correct.

**18. Solve the following equation: x−2=7**

A. 7

B. 2

C. 9

D. 11

**Answer: C**

**Explanation: **

Given, x−2=7

Add 2 on both the sides, we get

x−2+2=7+2

⇒x=9

Hence, option C is correct.

**19. Solve the following equation: y+3=10**

A. 3

B. 7

C. 10

D. 13

**Answer: B**

**Explanation: **

Given, y+3=10

Subtracting 3 on both the sides, we get:

y+3−3=10−3

⇒y=7

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### Simple Equations Problems with Solutions

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### Simple Equations Quiz Questions

So, here we are providing the Quiz in the form of the Multiple Choice Questions. So, all the people can easily attempt it. And we even tried to cover different levels of Questions on the Topic. Therefore, all the aspirants can answer them. Well, as this is completely free, you can take as many times as you want to do so. Now, many of the competitors are failing to clear this section because they are clearly lacking the knowledge of the Formulae and other basic concepts. Now, try to take a look at the Formulae and memorize them. Then proceed and Check the problem. Analyze it. Then proceed to apply the formulae on the problem. And the real key here is having knowledge of the Formulae and Practise.

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