**Problems on Numbers Quiz Online Test: **In Aptitude, Problem on Numbers is quite a handful to crack. Now, here we are presenting you the Problems on Numbers Quiz Online Test along with some Formulae’s and Short Cut Tricks to solve the Problems easily. Therefore, for problems on numbers questions and answers with solutions and problems on numbers shortcuts you can totally rely on us. Down in this post, we have framed up a Problems on Numbers Quiz Online Test. So, all those people who are preparing for various Exams like AIIMS, IIT’s, IIM’s, SSC, UPSC’s, Banks, Police, Civil Services and others can use this help provided on this page.

## Problems on Numbers Quiz

Quiz Name |
Time and Distance |

Category |
Aptitude |

Number of Questions |
25 |

Time |
30 Minutes |

Exam Type |
MCQ (Multiple Choice Questions) |

## Problems on Numbers Online Aptitude Test

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**1. Find a number such that when 15 is subtracted from 7 times the number, the result is 10 more than twice the number.**

A. 5

B. 10

C. 15

D. 20

E. none

**Answer: A**

**Explanation:**

Let, the number be z, Then, 7z – 15 = 2z + 10

⇒ 5z = 25 ⇔ z = 5.

Hence, the required number is 5.

Hence, option A is correct.

**2. If the sum of two numbers is 42 and their product is 437, then find the absolute difference between the numbers.**

A. 4

B. 6

C. 8

D. 12

E. None

**Answer: A**

**Explanation:**

So, the required difference = 4.

Hence, option A is correct.

**3. The sum of two numbers is 15 and the sum of their squares is 113. find the numbers.**

A. 3 and 4

B. 4 and 6

C. 7 and 8

D. 8 and 10

E. None

**Answer: C**

**Explanation:**

**4. A boy multiplied 987 by a certain number and obtained 559981 as his answer. If in the answer both 98 are wrong and the other digits are correct , then the correct answer would be:**

A. 553681

B. 555181

C. 555681

D. 556581

E. None

**Answer: C**

**Explanation:**

987 = 3 * 7 * 47.

So, the required number must be divisible by each one of 3, 7, 47

553681 => (Sum of digits = 28, not divisible by 3)

555181 => (Sum of digits = 25, not divisible by 3)

555681 is divisible by each one of 3, 7, 47.

**5. 476 ** 0 is divisible by both 3 and 11.The non zero digits in the hundred’s and ten’s places are respectively:**

A. 6 and 2

B. 8 and 2

C. 6 and 5

D. 8 and 5

E. None

**Answer: D**

**Explanation:**

Let the number be 476ab0

476ab0 is divisible by 3

=> 4 + 7 + 6 + a + b + 0 is divisible by 3

=> 17 + a + b is divisible by 3 ————————(i)

476ab0 is divisible by 11

[(4 + 6 + b) -(7 + a + 0)] is 0 or divisible by 11

=> [3 + (b – a)] is 0 or divisible by 11 ————–(ii)

Substitute the values of a and b with the values given in the choices and select the values which satisfies both Equation 1 and Equation 2.

if a=6 and b=2,

17 + a + b = 17 + 6 + 2 = 25 which is not divisible by 3 — Does not meet equation(i).Hence this is not the answer

if a=8 and b=2,

17 + a + b = 17 + 8 + 2 = 27 which is divisible by 3 — Meet equation(i)

[3 + (b – a)] = [3 + (2 – 8)] = -3 which is neither 0 nor divisible by 11—Does not meet equation(ii).Hence this is not the answer

if a=6 and b=5,

17 + a + b = 17 + 6 + 5 = 28 which is not divisible by 3 — Does not meet equation (i) .

Hence this is not the answer

**6. The average of four consecutive even numbers is 27. find the largest of these numbers.**

A. 22

B. 24

C. 27

D. 30

E. None

**Answer: D**

**Explanation:**

Let the four consecutive even numbers be x, x + 2, x + 4 and x + 6.

Then, sum of these numbers = (27 × 4) = 108.

So, x + (x + 2) + (x + 4) + (x + 6) = 108 or 4x = 96 or x = 24.

So, the largest number = (x + 6) = 30.

Hence, option D is correct.

**7. The difference between the place value and the face value of 7 in the numeral 967452 is
**

A. 6393

B. 5831

C. 6993

D. 6339

E. None

**Answer: C**

**Explanation:**

(Place value of 7)-(face value of 7)

=7000-7=6993

**8. On dividing 2272 as well as 875 by 3-digit number N,we get the same remainder.The sum of the digits of N is:**

A. 13

B. 12

C. 11

D. 10

E. None

**Answer: D**

**Explanation:**

(2272-875) = 1397, is exactly divisible by N.

Now , 1397 = 11 x 127

The required 3-digit number is 127,the sum of digits is 10.

**9. Out of two numbers, 4 times the smaller one is less than 3 times the larger one by 5, If the sum of the numbers is larger than 6 times their difference by 6, find the two numbers.**

A. 55 and 58

B. 23 and 28

C. 59 and 43

D. 65 and 67

E. None

**Answer: C**

**Explanation:**

Let the number be x and y, such that x > y .

Then, 3x – 4y = 5 ….(1) and (x + y) – 6 (x – y) = 6

⇒ – 5x + 7y = 6 …..(2)

Solving (1) and (2), we get : x = 59 and y = 43.

Hence, the required numbers are 59 and 43.

Hence, option C is correct.

**10. The ratio between a two-digit number and the sum of the digits of that number is 4 : 1. If the digit in the unit’s is three more than the digit in the ten’s places, what is the number?**

A. 25

B. 36

C. 47

D. 58

E. None

**Answer: B**

**Explanation:**

Let the ten’s digit be x. then, unit’s digit = (x + 3).

Sum of the digits = x + (x + 3) = 2x + 3.

3x = 9 ⇒ x = 3

Hence, required number = 11x + 3 ⇒ 36

**11. Which of the following can be used to illustrate that not all prime numbers are odd?**

A. 1

B. 2

C. 3

D. 4

E. None

**Answer: B**

**Explanation:**

The only even numbers in the list are 2 and 4, but 4 is not a prime. So 2 can be used to illustrate the statement that all primes are not odd.

**12. If three numbers are added in pairs, the sums equal 10, 19 and 21. Find the numbers?**

A. 2, 3 and 5

B. 6, 8 and 10

C. 6, 4 and 15

D. 12, 9 and 15

E. None

**Answer: C**

**Explanation: **

**13. 50 is divided into two parts such that the sum of their reciprocal is 1/12 find the two parts**

A. 14, 36

B. 20, 30

C. 38, 12

D. 35, 15

E. None

**Answer: B**

**Explanation: **

**14. A number when divided by 296 leaves 75 as remainder.When the same number is divided by 37,the remainder will be:**

A. 1

B. 3

C. 5

D. 2

E. None

**Answer: A**

**Explanation:**

Let the Number be Y.

Then Y = 296 q + 75

= (37 x 8)q +( 37 x 2) + 1

= 37 (8q + 2) + 1

Thus, when the number is divided by 37, the remainder is 1

**15. If the number 517?324 is completely divisible by 3,then the smallest whole number in place of ? will be:**

A. 2

B. 1

C. 3

D. 7

E. None

**Answer: A**

**Explanation:**

Sum of digits = (5 + 1 + 7 + x + 3 + 2 + 4) = ( 22 + x ), which must be divisible by 3.

When x=2. [(22 + 2) = 24 is divisible by 3]

So, the answer is 2

**16. A number exceeds its two fifth by 75. The number is:**

A. 112

B. 150

C. 125

D. 100

E. None

**Answer: C**

**Explanation: **

**17. The largest 4 digit number exactly divisible by 88 is?**

A. 9944

B. 9768

C. 8888

D. 9988

E. None

**Answer: A**

**Explanation:**

The largest 4 digit number is = 9999

After dividing 9999 with 88, we get 55 as remainder

so largest 4 digit number divisible by 88 = 9999-55 = 9944.

**18. When a natural number n is divided successively by 4, 5 and 7, it leaves remainders of 2, 3 and 6 respectively. Find the least possible value of n such that it is greater than or equal to 800.**

A. 824

B. 800

C. 814

D. 834

E. None

**Answer: D**

**Explanation: **

**19. Out of two numbers, 4 times the smaller one is less than 3 times the larger one by 5, If the sum of the numbers is larger than 6 times their difference by 6, find the two numbers.**

A. 55 and 58

B. 23 and 28

C. 59 and 43

D. 65 and 67

E. None

**Answer: C**

**Explanation:**

Let the number be x and y, such that x > y .

Then, 3x – 4y = 5 ….(1) and (x + y) – 6 (x – y) = 6

⇒ – 5x + 7y = 6 …..(2)

Solving (1) and (2), we get : x = 59 and y = 43.

Hence, the required numbers are 59 and 43.

Hence, option C is correct.

**20. A number when divided by 779 gives a remainder 47. By dividing the same number by 19, what would be the remainder?**

A. 9

B. 7

C. 44

D. 2

E. None

**Answer: A**

**Explanation:**

Number = ( 779 x a) + 47, where “a” is the quotient

= (19 x 41 x a) + (19 x 2) + 9

= 19 x (41a + 2) + 9

= 19 x (New quotient) + 9

Required remainder = 9

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### Problems on Numbers – Aptitude Question and Answers

So, While Taking the Quiz Test, as aspirant can find the Question and Correct Answer there itself. So, eventually, this will reduce the Search burden on the Candidate. Along with the Correct Answer, we are also providing the Solution with necessary Explanation. And we are giving this Quiz in Objective Type. That is an aspirant will take the Quiz in Multiple Choice Type. So, this will be very easy for any of the candidate. Well, along with the Quiz, our team also provided you some Tricks, that will guide you solve the problems. And some Basic Formulae’s too. Check them for better preparation.

### Tricks to solve Problems on Numbers Aptitude

Now, many of you might have questions like Are Problems on Number in Aptitude necessary? Where can I get Aptitude Problems on Numbers Questions and Answers with Solutions? Where can I get the objective type and multiple choice Aptitude Problems on Numbers? Tricks to solve Problems on Numbers Aptitude? and all. Well, this single post is the answer to all your Questions. Now, here through this article, we are providing the Online Quiz Test. And this absolutely for Free. Therefore, all the people who are preparing for Various Entrance Exams and Recruitment Test can take this. And try to enhance your Problem Solving Skills in Aptitude Section.

### Problems on Numbers Formula’s

Now, here we are projecting some basic Formula’s. And these are very important. So, please try to Memorize them. So, that they will come Handy for you. Well, with the help of these following** Problems on numbers Formula’s**, an individual can easily solve the Problems on Numbers.

- (a – b)2 = (a2 + b2 – 2ab)
- (a + b)2 = (a2 + b2 + 2ab)
- (a + b) (a – b) = (a2 – b2 )
- (a3 + b3) = (a + b) (a2 – ab + b2)
- (a3 – b3) = (a – b) (a2 – ab + b2)
- (a + b + c)2 = a2 + b2 + c2 + 2 (ab + bc + ca)
- (a3 + b3 + c3 – 3abc) = (a + b + c) (a2 + b2 + c2 – ab – bc – ac)

So, above are the Basic Formulae. And try to use them and solve a problem. So, that you will also have an idea on how to use the each individual Formula. And by taking the Problems on Numbers Quiz Online Test and preparing these formula’s will help you best in clearing the Problems on Numbers Section in the Aptitude.

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