**Wipro Aptitude Questions and Answers For Freshers (2019,2020 batch):** Dear Job Aspirants, In this article we have provided you two sets of sample / model Wipro Quantitative Aptitude Questions in PDF format. Along with PDF’s, we have also provided around 30 questions in the below section with answers and explanation. These * Wipro Aptitude questions* will help you to understand what kind of questions may come in the actual written exam.

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Contents

## Wipro Aptitude Questions and Answers For Freshers

Nowadays there a heavy competition for getting a job in MNC. For the number of students, it’s a dream also. Therefore, competitors can prepare Wipro Quant Questions and Solutions for freshers 2019. Aspirants can download Wipro Questions and Answers for freshers with Explanation in PDF. However, practice all the questions, they may ask in placement written test. Wipro Aptitude Questions and Solutions with Explanation helps the students to crack the exam easily. Therefore, all the job seeker can practice Wipro Aptitude Questions and Solutions 2019.

**You Can Also Check: Wipro Placement Papers & Wipro Syllabus PDF**

### Wipro Quantitative Aptitude Questions and Solutions with Explanation

1.** Priya takes 8 hours to draw 60 pages on a computer while Parul takes 6 hours to draw 45 pages on a computer. If both are working together in how much time will they draw a lot of 120 pages?**

A. 8hrs

B. 7hrs

C. 9hrs

D. 11hrs

**Answer –** A. 8hrs

**Explanation:**

First, calculate no of pages they draw in one hour. For Priya, it is 60/8 and for parul, it is 45/6.

Now total pages they draw in one hour is 60/8 + 45/6 = 15

So to print 120 time they will take = 15*X = 120. So X = 8hrs

2.** A can finish a work in 15 days and B can finish the work in 25 days. Both of them start working together but B leaves the work 3 days prior to the completion. After how many days B quit the work.**

A. 7.5

B. 8

C. 8.5

D. 9

**Answer –** A. 7.5

**Explanation:**

Let ‘X’ days they take to complete the whole work.

(1/15 + 1/25)*(X-3) + 3* (1/15), X = 10.5 days. So he quits after 7.5 days.

3. **A contractor undertook a job and employed 40 men to do a piece of work in 80 days. But after 60 days he found that only 3/5 of the work is completed. To complete the work in time, how many more men he should employ.**

A. 15

B. 20

C. 25

D. 40

**Answer –** D. 40

**Explanation:**

(40*60)/3 = (x*20)/2

x=80

No of men required=80-40 =40

4. **P, Q, and R can complete a piece of work in 9, 18 and 27 days respectively. After 1/3 work is completed P left the work and the remaining work is completed by Q and R together. Find the days required to complete the remaining work.**

A. 36/7

B. 35/6

C. 36/5

D. 32/5

**Answer –** C. 36/5

**Explanation:**

1/3 work is completed so remaining work is 2/3. As P left the job so the remaining work will be completed by Q and R. Take X no. of days Q and R take to complete the work.

(1/18 + 1/27)*X = 2/3. So, X = 36/5

5. **A is 25% more efficient than B. C does half the work done by A & B together. If C alone does the work n 30 days, then A alone can do the work in**

A. 32 days

B. 27 days

C. 22 days

D. 25(1/2) days

E. None of these

**Answer –** B. 27 days

**Explanation:**

A’s one day’s work:B’s one days work = 125:100 = 5:4

Let A’s & B’s one day’s work be 5x and 4x days

Then C’s one day’s work = 9x/2

= > 9x/2 = 1/30

= > x = ((1/30)*(2/9)) = 1/135

A’s one day’s work = 5/135 = 1/27

Therefore, A alone can do the work in 27 days

6. **P can finish a work in 27 days, Q in 9 days and C in 12 days. Q & R start the work but are forced to leave after 4 days. The remaining work was done by P in:**

A. 6 days

B. 9 days

C. 10 days

D. 12 days

E. None of these

**Answer –** A. 6 days

**Explanation:**

(Q+R) one day’s work = 1/9+1/12 = 7/36

Q & R in 3 days = 4*7/36 = 7/9

Remaining work = 1-(7/9) = 2/9

1/27 work is done by A in 1 day.

2/9 work is done by A in 27*2/9 = 6 days

7.** 4 men and 6 women can complete a work in 8 days, while 3 men and 7 women can complete it in 10 days. In how many days will 20 women complete it?**

A. 10 days

B. 15 days

C. 20 days

D. 25 days

E. None of these

**Answer –** C. 20 days

**Explanation:**

1 man’s 1 day’s work = x days

1 woman’s 1 day’s work = y

Then, 4x+6y = 1/8 and 3x+7y = 1/10.

Solving these two equations y = 1/400

1 woman’s 1 day’s work = 1/400

20 women = 20/400 = 1/20 = 20 days

Therefore, 20 women can complete the work in 20 days.

8. **A boat takes 120min less to travel 30km downstream than to travel the same distance upstream. If the speed of the boat in still water is 8kmph then the speed of the stream is**

A. 2 kmph

B. 8 kmph

C. 3 kmph

D. 4 kmph

E. None of these

**Answer –** A. 2 kmph

**Explanation:**

The speed of the stream = x

(30/8-x) – (30/8+x)= 120/60 = 2/1

30(8+x) – 30(8-x) = 2[64 – x2] 240+30x-240x+30x = 2[64 – x2] 60x = 128- 2×2

2×2+60x-128 = 0

x2+30x-64 = 0

(x+32)(x-2) = 0

X=2 kmph

9.** A boat running downstream covers a distance of 24km in 4hrs, while for covering the same distance upstream it takes 6hrs, what is the speed of the boat in still water?**

A. 12 kmph

B. 10 kmph

C. 5 kmph

D. 7 kmph

E. None of these

**Answer –** C. 5kmph

**Explanation:**

24/x-y = 6

6x – 6y = 24———–(1)

24/x+y = 4

4x+4y = 24—————–(2)

24x – 24y = 96

24x+24y = 144

Solve above 2 equations

48x = 240

X = 240/48 = 5

10.** A boat can travel 4.2km upstream in 14min. If the ratio of the speed of the boat in still water to the speed of the stream is 7:1. How much time will the boat take to cover 17.6km downstream?**

A. 56 min

B. 44 min

C. 32 min

D. 48 min

E. None of these

**Answer –** B. 44 min

**Explanation:**

Speed = 7x:x

Downstream = 8x; upstream = 6x

Upstream speed = 4.2*60/14 = 18kmph

6x = 18

X = 3

Downstream = 8*3 = 24

Time taken for 17.6km = 17.6*60/24 = 44min

11.** A man can row at 4 kmph in still water. If the velocity of the current is 1 kmph and it takes him 1 hour to row to a place and come back. how far is that place?**

A. 1.8 km

B. 2.6 km

C. 1.5 km

D. 3.2 km

E. None of these

**Answer –** A. 1.8 km

**Explanation:**

Let the distance is x km

Rate downstream = 4 + 1 = 5 kmph

Rate upstream = 4 – 1 = 3 kmph

then

x/5 + x/3 = 1

3x + 5x = 15

x = 15/8 = 1.8 km

12. **Arun takes thrice as long to row a distance against the stream as to row the same distance in favor of the stream. The ratio of the speed of the boat in still water and stream is**

A. 3:1

B. 1:2

C. 2:1

D. 2:3

E. None of these

**Answer –** C. 2:1

**Explanation :**

speed downstream = x kmph

Speed upstream = 3x kmph

(3x+x)/2 : (3x-x)/2

4x/2 : 2x/2 = 2:1

Therefore, The ratio of the speed of the boat in still water and stream is 2:1

13.** A boat takes 30 hours for traveling downstream from point A to point B and coming back to point C midway between A and B. If the velocity of the stream is 2 kmph and the speed of the boat in still water is 15 kmph, what is the distance between A and B?**

A. 342 km

B. 356 km

C. 316 km

D. 308 km

E. None of these

**Answer –** D. 308 km

**Explanation :**

The velocity of the stream = 2 kmph

The speed of the boat in still water is 15 kmph

Speed downstream = (15+2) = 17 kmph

Speed upstream = (15-2) = 13 kmph

Let the distance between A and B be x km

x/17+(x/2)/13=30

x/17+x/26=30

43x/442=30

x=30*442/43 = 308.37 = 308km

Therefore, Distance between A and B = 308 km

14.** A train running with 72km/hr takes 20sec to cross a platform 200 m long. How much it takes to cross a stationary train having twice the length of the platform.**

A. 20 sec

B. 30 sec

C. 40 sec

D. 50 sec

E. None of these

**Answer –** B. 30 sec

**Explanation :**

200+L = 72*(5/18)*20. L= 200m.

400 + 200 = 72*(5/18)*t. So, t = 30 sec

Therefore, the time taken to cross a stationary train is 30 sec.

15. **A train traveling with 54 km/hr takes 20 seconds to cross a bridge. Another train 70-meter shorter crosses the same bridge at 36 km/hr. Find the time taken by the second train to cross the bridge.**

A. 23 sec

B. 24 sec

C. 25 sec

D. 26 sec

E. None of these

**Answer –** A. 23 sec

**Explanation :**

Let L and B are lengths of train and bridge respectively.

L + B = 54*5/18*20 = 300 meter

L + B – 70 = 36*5/18*t = 230, so we get t = 23 sec

Therefore, the time taken by the second train to cross the bridge is 23 sec.

16. **20 by weight. He in total gets 20% profit by selling the first two and at last, he finds he has no gain or no loss in selling the whole quantity which he had. What was the percentage loss he suffered for the third quantity?**

A. 30%

B. 40%

C. 20%

D. 50%

**Answer –** B. 40%

**Explanation:**

Total quantity rate =

(12 * 100 + 15 * 80 + 20 * 60) = 3600

For first 2 quantity, (12 * 100) + (15 * 80) = 2400

But he gets 20% profit = 2400 * 1.2 = 2880

So the third quantity = 3600 – 2880 = 720

Actual third quantity rate = 20 * 60 = 1200

Loss suffered = (1200 – 720) / 1200

= 480/1200 = 40 %

Therefore, the percentage of loss he suffered for the third quantity is 40%.

17.** Rs.1200 is divided among A, B, C so that A receives half so much as B and B half as much as C. Then B’s share is**

A. Rs.423

B. Rs.343

C. Rs.356

D. Rs.387

E. None of these

**Answer –** B. Rs.343

**Explanation:**

Let C = x

x: 2X : 4X = 1:2 :4

B =1200*2/7 = 342.8 = 343

Therefore, the share of B is 343

18.** Naren received Rs.8000 as his share out of the total profit of Rs.12000 which he and Praba earned at the end of one year. If Naren invested Rs.20,000 for 6 months, whereas Praba invested his amount for the whole year, what was the amount invested by Praba?**

A. Rs.2,000

B. Rs.8,000

C. Rs.6,000

D. Rs.5,000

E. None of these

**Answer –** D. Rs.5,000

**Explanation :**

P = 8000:4000 = 2:1

20000*6 : x*12 = 2:1

20000:2x = 2:1

20000/2x =2/1

2X = 20000*1/2 =>x = 5,000

Therefore, the amount invested by Praba is 5,000.

19.** A, B, and C started a shop by investing Rs.27000, Rs.48000 and Rs.63000 respectively. At the end of the year, the profits were distributed among them. If B’s share of profit be Rs.19200, then the total profit was**

A. Rs.55000

B. Rs.52000

C. Rs.52550

D. Rs.55200

E. None of these

**Answer –** D. Rs.55200

**Explanation :**

A:B:C = 27:48:63 = 9:16:21

16x/46 = 19200

X = 19200*46/16 = 55200

Therefore, the total profit is Rs. 55200

20.** A sum of money is divided among P, Q, R and S in the ratio 5:4:7:9 respectively. If the share of P is Rs.2300 more than that of Q, then what is the total amount of R and S together?**

A. Rs.36800

B. Rs.36000

C. Rs.35000

D. Rs.37200

E. None of these

**Answer –** A. Rs.36800

**Explanation :**

5x-4x = 2300

X = 2300

R = 7*2300 = 16100

S = 9*2300 = 20700

R+S = 36800

Therefore, the total amount of R and S together is Rs. 36800.

21. **A box contains 30 electric bulbs, out of which 8 are defective. Four bulbs are chosen at random from this box. Find the probability that at least one of them is defective?**

A. 432/783

B. 574/783

C. 209/784

D. 334/784

E. None of these

**Answer –** B. 574/783

**Explanation :**

1 – 22c4/30c4 = 1 – 209/783 = 574/783

22. **Two person A and B appear in an interview. The probability of A’s selection is 1/5 and the probability of B’s selection is 2/7. What is the probability that only one of them is selected?**

A. 11/35

B. 12/35

C. 13/35

D. 17/35

E. None of these

**Answer –** C. 13/35

**Explanation :**

A selects and B rejects + B selects and A rejects = (1/5)*(5/7) + (4/5)*(2/7) = 13/35

23. **An apartment has 8 floors. An elevator starts with 4 passengers and stops at 8 floors of the apartment. What is the probability that all passengers travel on different floors?**

A. 109/256

B. 135/256

C. 105/256

D. 95/256

E. None of these

**Answer –** C. 105/256

**Explanation :**

Total outcomes = 8*8*8*8

Favorable outcomes = 8*7*6*5 (the first person having 8 choices, after that second person have 7 choices and so on)

So, probability = 105/256

24.** A speak truth in 60% cases and B in 80% cases. In what percent of cases they likely to contradict each other narrating the same incident?**

A. 9/25

B. 7/25

C. 11/25

D. 13/25

E. None of these

**Answer –** C. 11/25

**Explanation :**

P(A) = 3/5 and P(B) = 4/5. Now they are contradicting means one is telling truth and others telling the lie. So,

Probability = (3/5)*(1/5) + (2/5)*(4/5)

25. **A 4- digit number is formed by the digits 0, 1, 2, 5 and 8 without repetition. Find the probability that the number is divisible by 5.**

A. 1/5

B. 2/5

C. 3/5

D. 4/5

E. None of these

**Answer –** B. 2/5

**Explanation :**

Total possibility = 5*4*3*2

Favorable outcomes = 2*4*3*2 (to be divisible by 5 unit digit can be filled with only 0 or 5, so only two possibilities are there, then the remaining can be filled in 4, 3 and 2 ways respectively)

so probability = 2/5

26. **A bag contains 8 blue and 7 green balls. 2 balls are drawn one by one without replacement. What is the probability that the balls are alternate of different colors?**

A. 9/21

B. 8/17

C. 5/14

D. 8/15

E. 9/19

**Answer –** D. 8/15

**Explanation:**

When 1st is a blue, prob. = 8/15 * 7/14 = 4/15

When 1st is a green, prob. = 7/15 * 8/14= 4/15

Add both cases = 8/15

27.** A bag contains 8 blue and 7 green balls. A ball is drawn out of it and put back in the bag. Then a ball is drawn again. What is the probability that both the balls are green?**

A. 36/225

B. 48/221

C. 49/225

D. 40/221

E. None of these

**Answer –** C. 49/225

**Explanation:**

7/15 * 7/15 = 49/225

28. **The batting average of a batsman for 20 innings is 35 and the difference b/w the runs of best inning and worst inning is 50. If these two innings are not included the average becomes 32 for 18 innings. The best score of the batsman is.**

A. 91

B. 77

C. 87

D. 82

**Answer –** C. 87

**Explanation :**

35*20 = 700.

Best(B) – Worst(W) = 50

700 – B – H = 18*32= 576. B+H = 124 and B-H = 50. So B =87

29. **The average age of 5 children of a family is 10 years but if we include the age of father and mother then the average age becomes 22 years. It is given that father age is 6 years more than the mother so what will be the age of mother at present.**

A. 47

B. 48

C. 49

D. 50

**Answer –** C. 49

**Explanation :**

the sum of age of children = 50

50 + M+ F = 22*7 = 154.

M+F = 104 and F= M+6 . So, M = 49

30. **The average age of a class of 20 students is 12 years. Out of which, one student whose age is 10 year left the class and two new boys entered the class. The average of the class remains the same and the difference between the ages of new boys is 4 year. What will be the age of the younger one?**

A. 8

B. 9

C. 10

D. 11

**Answer –** B. 9

**Explanation :**

240 – 10 + a+ b = 21 * 12

a+ b =22, a-b = 4. So, b= 9

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**You can also check: Wipro Aptitude Questions PDF & Wipro Reasoning Questions**

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